Practice question

Absorbance and transmittance are linked logarithmically via Beer-Lambert relationship: A = -log10 T = 2 - log10(%T). Rearranged, transmittance T = 10 raised to power -A, percent transmittance equals 100 multiplied by 10^-A. Substituting A equals one yields T equals 0.1 fraction corresponding to ten percent. For A equals two, T equals 10^-2 equals 0.01 fraction, corresponding to one percent transmittance meaning ninety-nine percent light absorbed. This steep tenfold reduction per absorbance unit explains why accuracy declines above A beyond two due to stray light and detector noise in routine measurements.