NCERT SOLUTIONS FOR CLASS 11 MATHS CHAPTER 1 | SETS EX 1.5 |

Question 1. Let U = {1, 2, 3, 4, 5, 6, 7, 8, 9}, A = { 1, 2, 3, 4}, B = (2,4,6,8} and C = {3,4,5,6}. Find

  • (i) A’
  • (ii) B’
  • (iii) (A ∪ C)’
  • (iv) (A ∪B)’
  • (v) (A’)’
  • (vi) (B – C)’

Solution.

Here U = {1, 2, 3, 4, 5, 6, 7, 8, 9}, A = {1, 2, 3, 4}, B = {2, 4, 6, 8} and C ={3, 4, 5, 6}

(i) A’=U – A

= {1, 2, 3, 4, 5, 6, 7, 8, 9} – {1, 2, 3, 4}

= {5, 6, 7, 8, 9}

(ii) B’=U – B
= {1, 2, 3, 4, 5, 6, 7, 8, 9} – {2, 4, 6, 8}
= {1, 3, 5, 7, 9}

(iii) A ∪ C = {1, 2, 3, 4} ∪ {3, 4, 5, 6}
= (1, 2, 3, 4, 5, 6}
(A∪C)’=U-(A∪C)
= {1, 2, 3, 4, 5, 6, 7, 8, 9} – {1, 2, 3, 4, 5, 6}
= {7, 8, 9}

(iv) A ∪ B = {1, 2, 3,4} ∪ {2, 4, 6, 8}
= {1, 2, 3, 4, 6, 8}
(A∪B)’ = U – (A∪B)
= {1, 2, 3, 4, 5, 6, 7, 8, 9} – {1, 2, 3, 4, 6, 8}
= {5, 7, 9}

(v) We know that A’ = {5, 6, 7, 8, 9}
(A’)’ =U – A’
= {1, 2, 3, 4, 5, 6, 7, 8, 9} – {5, 6, 7, 8, 9}
= {1, 2, 3, 4}

(vi) B – C = {2, 4, 6, 8} – {3, 4, 5, 6} = {2, 8}
(B-C)’=U – (B-C)
= {1, 2, 3, 4, 5, 6, 7, 8, 9} – {2, 8}
= {1, 3, 4, 5, 6, 7, 9}.

Question 2. If U = {a,b, c, d, e, f, g, h}, find the complements of the following sets:

  • (i) A = {a, b, c}
  • (ii) B = {d, e, f, g}
  • (iii) C = {a, c, e, g}
  • (iv) D = {f, g, h, a}

Solution.

(i) A’ = U – A = {a, b, c, d, e, f, g, h} – {a, b, c}

= {d, e,f, g, h}

(ii) B’ = U – B = {a, b, c, d, e,f, g, h} – {d, e, f, g}
= {a, b, c, h}

(iii) C’ = U – C = {a, b, c, d, e, f, g, h} – {a, c, e, g}
= {b, d, f, h}

(iv) D’ = U – D = {a, b, c, d, e, f, g, h} – {f, g, h, a}
= {b, c, d, e}.

Question 3. Taking the set of natural numbers as the universal set, write down the complements of the following sets:

  • (i) {x: x is an even natural number}
  • (ii) {x: x is an odd natural number}
  • (iii) {x: x is a positive multiple of 3}
  • (iv) {x: x is a prime number}
  • (v) {x: x is a natural number divisible by 3 and 5}
  • (vi) {x: x is a perfect square}
  • (vii) {x: x is a perfect cube}
  • (viii) {x: x + 5 = 8}
  • (ix) (x: 2x + 5 = 9)
  • (x) {x: x ≥ 7}
  • (xi) {x: x ∈ W and 2x + 1 > 10}

Solution.

NCERT Solutions for Class 11 Maths Chapter 1 Sets Ex 1.5 1
NCERT Solutions for Class 11 Maths Chapter 1 Sets Ex 1.5 2
NCERT Solutions for Class 11 Maths Chapter 1 Sets Ex 1.5 3

Question 4. If U = {1, 2, 3, 4, 5, 6, 7, 8, 9}, A = {2, 4, 6, 8} and B = {2, 3, 5, 7}. Verify that

  • (i) (A ∪ B)’ = A’∩B’
  • (ii) (A ∩ B)’ = A’∪B’

Solution.

NCERT Solutions for Class 11 Maths Chapter 1 Sets Ex 1.5 4
NCERT Solutions for Class 11 Maths Chapter 1 Sets Ex 1.5 5

Question 5. Draw appropriate Venn diagram for each of the following:

  • (i) (A ∪ B)’
  • (ii) A’∩B’
  • (iii) (A ∩ B)’
  • (iv) A’ ∪ B’

Solution.

NCERT Solutions for Class 11 Maths Chapter 1 Sets Ex 1.5 6
NCERT Solutions for Class 11 Maths Chapter 1 Sets Ex 1.5 7

Question 6. Let U be the set of all triangles in a plane. If A is the set of all triangles with at least one angle different from 60°, what is A’?

Solution.

Here U = {x : x is a triangle}

A = {x: x is a triangle and has at least one angle different from 60°}

∴ A’ = U – A = {x : x is a triangle} – {x : x is a triangle and has atleast one angle different from 60°}

= {x : x is a triangle and has all angles equal to 60°)

= Set of all equilateral triangles.

Question 7. Fill in the blanks to make each of the following a true statement:

  • (i) A ∪ A’ = …….
  • (ii) φ’ ∩ A = .…….
  • (iii) A ∩ A’ = …….
  • (iv) U’ ∩ A = .…….

Solution.

(i) A ∪ A’= U

(ii) φ’ ∩ A = U ∩ A = A

(iii) A ∩ A’ = φ

(iv) U’ ∩ A = φ ∩ A = φ