CLASS 10 MATH NCERT SOLUTIONS FOR CHAPTER – 11 Constructions Ex – 11.1

Constructions

Question 1.
Draw a line segment of length 7.6 cm and divide it in the ratio 5:8. Measure the two parts.

Solution:
NCERT Solutions For Class 10 Maths Chapter 11 Pdf Constructions Ex 11.1 Q1

Question 2.
Construct a triangle of sides 4 cm, 5 cm and 6 cm and then a triangle similar to it whose sides are 23 of the corresponding sides of the first triangle.

Solution:
NCERT Solutions For Class 10 Maths Chapter 11 Pdf Ex 11.1 Q2
NCERT Solutions For Class 10 Maths Chapter 11 Pdf Ex 11.1 Q2.1

Question 3.
Construct a triangle with sides 5 cm, 6 cm, and 7 cm and then another triangle whose sides are 75 of the corresponding sides of the first triangle.

Solution:
Ex 11.1 Class 10 NCERT Solutions PDF Q3
Ex 11.1 Class 10 NCERT Solutions PDF Q3.1

Question 4.
Construct an isosceles triangle whose base is 8 cm and altitude 4 cm and then another triangle whose sides are 112 times the corresponding sides of the isosceles triangle.

Solution:
Exercise 11.1 Class 10 NCERT Solutions PDF Q4
Exercise 11.1 Class 10 NCERT Solutions PDF Q4.1

Question 5.
Draw a triangle ABC with side BC = 6 cm, AB = 5 cm and ∠ABC = 60°. Then construct a triangle whose sides are 34 of the corresponding sides of the triangle ABC.

Solution:
Constructions Class 10 NCERT Solutions Ex 11.1 PDF Q5 Constructions Class 10 NCERT Solutions Ex 11.1 PDF Q5.1

Question 6.
Draw a triangle ABC with side BC = 7 cm, ∠B = 45°, ∠A = 105°. Then, construct a triangle whose sides are 43 times the corresponding sides of ∆ABC.

Solution:
Chapter 11 Maths Class 10 NCERT Solutions Exercise 11.1 PDF Q6
Chapter 11 Maths Class 10 NCERT Solutions Exercise 11.1 PDF Q6.1

Question 7.
Draw a right triangle in which the sides (other than hypotenuse) are of lengths 4 cm and 3 cm. Then construct another triangle whose sides are 53F times the corresponding sides of the given triangle.

Solution:
Steps of Construction:
1. Construct a ∆ABC, such that BC = 4 cm, CA = 3 cm and ∠BCA = 90°
2. Draw a ray BX making an acute angle with BC.
3. Mark five points B1, B2, B3, B4 and B5 on BX, such that BB1 = B1B2 = B2B3 = B3B4 = B4B5.
4. Join B3C.
5. Through B5, draw B5C’ parallel to B3C intersecting BC produced at C’.
6. Through C’, draw C’A’ parallel to CA intersecting AB produced at A’.
Thus, ∆A’BC’ is the required right triangle.
NCERT Solutions for Class 10 Maths Chapter 11 Constructions Ex 11.1 Q7
Justification:
NCERT Solutions for Class 10 Maths Chapter 11 Constructions Ex 11.1 Q7.1